1주차 보너스 - Palindrome 순열

문제

Given a string, determine if a permutation of the string could form a palindrome.

Input: "code"
Output: false

Input: "aab"
Output: true

Input: "carerac"
Output: true

내 테스트

import pytest
from .Week1Bonus import Solution

s = Solution()


@pytest.mark.parametrize("test_input", ["code", "abc"])
def test_cannot_permute(test_input):
    assert not s.canPermutePalindrome(test_input)


@pytest.mark.parametrize("test_input", ["aab", "carerac", "a", "aa"])
def test_can_permute(test_input):
    assert s.canPermutePalindrome(test_input)

내 솔루션

class Solution:
    def canPermutePalindrome(self, s: str) -> bool:
        if len(s) == 1:
            return True
        char_counts = {}
        for c in s:
            if c in char_counts:
                char_counts[c] = char_counts[c] + 1
            else:
                char_counts[c] = 1
        values = char_counts.values()
        num_odd = 0

        for n in values:
            if n == 1 or n % 2 != 0:
                num_odd += 1

        return num_odd < 2

분석

내 해설