POJ 2260 (ZOJ 1949) Error Correction 문제 하나

Description
A boolean matrix has the parity property when each row and each column has an even sum, i.e. contains an even number of bits which are set. Here’s a 4 x 4 matrix which has the parity property: 1 0 1 0
0 0 0 0
1 1 1 1
0 1 0 1
The sums of the rows are 2, 0, 4 and 2. The sums of the columns are 2, 2, 2 and 2. Your job is to write a program that reads in a matrix and checks if it has the parity property. If not, your program should check if the parity property can be established by changing only one bit. If this is not possible either, the matrix should be classified as corrupt.
Input
The input will contain one or more test cases. The first line of each test case contains one integer n (n<100), representing the size of the matrix. On the next n lines, there will be n integers per line. No other integers than 0 and 1 will occur in the matrix. Input will be terminated by a value of 0 for n. Output
For each matrix in the input file, print one line. If the matrix already has the parity property, print “OK”. If the parity property can be established by changing one bit, print “Change bit (i,j)” where i is the row and j the column of the bit to be changed. Otherwise, print “Corrupt”. Sample Input
4 1 0 1 0 0 0 0 0 1 1 1 1 0 1 0 1 4 1 0 1 0 0 0 1 0 1 1 1 1 0 1 0 1 4 1 0 1 0 0 1 1 0 1 1 1 1 0 1 0 1 0 Sample Output
OK Change bit (2,3) Corrupt
처음에 나는 제목이 무슨 뜻인지 알아보지 못하고 오랫동안 생각했는데 나중에야 깨달았다. 바로 한 줄, 한 열의 합이 짝수라는 것이다. 만약 모두 그렇다면 OK를 출력하는 것이다.만약 숫자를 바꾸어 모든 행렬을 짝수로 만들 수 있다면, 출력은 그 글자의 줄과 열을 수정해야 한다.못하면 Corrupt를 출력합니다.아주 물 한 문제,,...왜 영어를 못해!!코드 첨부:

#include <iostream>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
using namespace std;

int main(){
    int n,m;
    bool s[105][105];
    short int a[105],b[105];
    bool a1[105],b1[105];
    while(cin>>n&&n!=0){
            int hang=0;
            int lie=0;
        for(int i=0;i<n;i++){
                a[i]=0;
            for(int j=0;j<n;j++){
                scanf("%d",&s[i][j]);
                a[i]+=s[i][j];
            }
        }
        for(int j=0;j<n;j++){
                b[j]=0;
            for(int i=0;i<n;i++){
                b[j]+=s[i][j];
            }
        }
        for(int i=0;i<n;i++){
            a1[i]=1;
            b1[i]=1;
            if(a[i]%2!=0){
                a1[i]=0;
            }
            if(b[i]%2!=0){
                b1[i]=0;
            }
        }
        int flag1 = 0, flag2=0;
        int hang1,lie1;
        for(int i=0;i<n;i++){
            if(a1[i]==0){
                hang++;
                if(flag1==0){
                    hang1=i+1;
                }
            }
            if(b1[i]==0){
                lie++;
                if(flag2==0){
                    lie1=i+1;
                }
            }
        }
        if(hang==1&&lie==1){
            printf("Change bit (%d,%d)
",hang1,lie1);
        }else if(hang==0&&lie==0){
            printf("OK
");
        }
        else{
            printf("Corrupt
");
        }
    }
    return 0;
}