HR - Day of the Programmers

Marie invented a Time Machine and wants to test it by time-traveling to visit Russia on the Day of the Programmer (the 256th day of the year) during a year in the inclusive range from 1700 to 2700.

From 1700 to 1917, Russia's official calendar was the Julian calendar; since 1919 they used the Gregorian calendar system. The transition from the Julian to Gregorian calendar system occurred in 1918, when the next day after January 31st was February 14th. This means that in 1918, February 14th was the 32nd day of the year in Russia.

In both calendar systems, February is the only month with a variable amount of days; it has 29 days during a leap year, and 28 days during all other years. In the Julian calendar, leap years are divisible by 4; in the Gregorian calendar, leap years are either of the following:

• Divisible by 400.
• Divisible by 4 and not divisible by 100.

Given a year,y , find the date of the 256th day of that year according to the official Russian calendar during that year. Then print it in the format dd.mm.yyyy, where dd is the two-digit day, mm is the two-digit month, and yyyy is y.

For example, the given year = 1984. 1984 is divisible by 4, so it is a leap year. The 256th day of a leap year after 1918 is September 12, so the answer is12.09.1984 .

예시

INPUT_0

2017

OUTPUT_0

13.09.2017

INPUT_1

2016

OUTPUT_1

12.09.2016

풀이

• 그레고리력과 율리우스력의 윤년을 구하는 문제이다.
• 1917년을 기준으로 나눠 윤년을 구한다.
• 윤년 여부에 따라 각기 다른 지정된 날짜를 출력한다.
• 1918년은 율리우스력에서 그레고리력으로 바뀐 해이므로 예외 조건을 준다.

코드

function dayOfProgrammer(year) {
    const leapYearDays = [31, 29, 31, 30, 31, 31, 30, 31, 31];
    const yearDays = [31, 28, 31, 30, 31, 31, 30, 31, 31];
    let thisYearDays;
    

    if (year > 1917) {  // 그레고리안 력
        if ((year % 4 === 0 && year % 100 !== 0) || year % 400 === 0) {
            thisYearDays = leapYearDays;
        } else {
            thisYearDays = yearDays;
        }
    }

    if (year <= 1917) {  // 줄리안 력
        if (year % 4 === 0) {
            thisYearDays = leapYearDays;
        } else {
            thisYearDays = yearDays;
        }
    }

    if (year === 1918) {
        return `26.09.${year}`;
    }

    const programmerDay = thisYearDays[1] === 28 ? `13.09.${year}` : `12.09.${year}`;
    return (programmerDay);
}