항주 전기 1047 An Easy Task-자바 해독

An Easy Task
Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 17866    Accepted Submission(s): 11383
Problem Description
Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?
Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.
Note: if year Y is a leap year, then the 1st leap year is year Y.
 
Input
The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains two positive integers Y and N(1<=N<=10000).
 
Output
For each test case, you should output the Nth leap year from year Y.
 
Sample Input

   
   
   
   

    
    
    
    3
2005 25
1855 12
2004 10000
   
   
   
   

 
Sample Output

   
   
   
   

    
    
    
    2108
1904
43236


    
    
    
    
 
     
 
      Hint 
     
 We call year Y a leap year only if (Y%4==0 && Y%100!=0) or Y%400==0. 
    
    
    
    
     
   
   
   
   
   
   
   
   

    
    
    
     
   
   
   
   
   
   
   
   

    
    
    
         ：                ，             ，        ：    4   0    100    0，     400    ，              。
   
   
   
   

import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;

public class Main{

	public static void main(String[] args) {

		Scanner scanner = new Scanner(System.in);
		int num = scanner.nextInt();
		int i = 0, num_year = 0, num_times = 0, count = 0;
		List<Integer> list = new ArrayList<Integer>();
		while(i < num)
		{
			count = 0;
			num_year = scanner.nextInt();
			num_times = scanner.nextInt();
			while(count < num_times)
			{
				 
				 if (num_year%4==0 && num_year%100!=0 || num_year%400==0)
				 {
					 count++;
				 }
				 
				 if(count == num_times)
				 {
					 list.add(num_year);
				 }
				 num_year ++;
			}
			i++;
		}
		for(i = 0; i < list.size(); i++)
		{
			System.out.println(list.get(i));
		}
	}

}