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3236 단어 데이터 구조
We have a network of computers and a list of bi-directional connections. Each of these connections allows a file transfer from one computer to another. Is it possible to send a file from any computer on the network to any other?
Input Specification:
Each input file contains one test case. For each test case, the first line contains N (2≤N≤10​4​​), the total number of computers in a network. Each computer in the network is then represented by a positive integer between 1 and N. Then in the following lines, the input is given in the format:
I c1 c2  

where  I  stands for inputting a connection between  c1  and  c2 ; or
C c1 c2    

where  C  stands for checking if it is possible to transfer files between  c1  and  c2 ; or
S

where  S  stands for stopping this case.
Output Specification:
For each  C  case, print in one line the word "yes" or "no" if it is possible or impossible to transfer files between  c1  and  c2 , respectively. At the end of each case, print in one line "The network is connected." if there is a path between any pair of computers; or "There are  k  components." where  k  is the number of connected components in this network.
Sample Input 1:
5
C 3 2
I 3 2
C 1 5
I 4 5
I 2 4
C 3 5
S

Sample Output 1:
no
no
yes
There are 2 components.

Sample Input 2:
5
C 3 2
I 3 2
C 1 5
I 4 5
I 2 4
C 3 5
I 1 3
C 1 5
S

Sample Output 2:
no
no
yes
yes
The network is connected.

답 은 다음 과 같다.
#include 
#include 
#define MAXN 10001
int FindRoot(int S[],int indix){
	int temp=indix;
	if(S[indix]<0) return indix;
  	else
  		for (;S[indix]>0;indix=S[indix]);
	S[temp]=indix;//    
	return indix;
}

void Union( int S[],int indix1,int indix2){
	int root1,root2;
	root1=FindRoot(S,indix1);
	root2=FindRoot(S,indix2);
	if(root1!=root2){
		/*          */
		if(S[root1]-S[root2]<=0){
			S[root2]+=S[root1];
			S[root1]=root2;
		}
		else{
			S[root1]+=S[root2];
			S[root2]=root1;
		}			
	}
}
void IsConnect(int S[],int indix1,int indix2){
	int root1,root2;
	root1=FindRoot(S,indix1);
	root2=FindRoot(S,indix2);
	if(root1!=root2)
		printf("no
"); else printf("yes
"); } int main(){ int N,i,j,part=0; int S[MAXN]; scanf("%d
",&N); int k; for (k=1;k<=N;k++) S[k]=-1; char ch; scanf("%c",&ch); while(ch!='S'){ if(ch=='I'){ scanf("%d %d",&i,&j); getchar(); Union(S,i,j); } else{ scanf("%d %d",&i,&j); getchar(); IsConnect(S,i,j); } scanf("%c",&ch); } for (k=1;k<=N;k++) { if(S[k]<0) part++; //printf("%d ",S[k]); } if(part==1) printf("The network is connected."); else printf("There are %d components.",part); return 0; }

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