문제

https://programmers.co.kr/learn/courses/30/lessons/12948

접근

문자열 슬라이싱

코드

python

def solution(phone_number):
    star = "*" * len(phone_number[0:-4])
    return star + phone_number[-4:]

js

function solution(phone_number) {
    let star = ""
    const starLen = phone_number.slice(0, -4).length;
        
    for(var i=0; i<starLen; i++){
        star += "*"
    }
    
    return star + phone_number.slice(-4);
    
}

python 슬라이싱

phone_number = "01012345678"

phone_number[0:-4]
# "0101234"

phone_number[-4:]
# 5678

js 슬라이싱

const a = "0123456789"

a.slice(0,8)
// "01234567"

a.slice(8)
// "89"

a.slice(0, -5)
// "01234"

a.slice(-5)
// "56789"

a.slice(-5, 9)
// "5678"

a.slice(5, -1)
// "5678"

a.slice(5, -2)
// "567"

a.slice(5, -4)
// "5"

a.slice(5, -5)
// ""