[Data Structures and Algorithms] 7-3 Pop Sequence(25점)

2242 단어
7-3 Pop Sequence(25점)
Given a stack which can keep M numbers at most. Push N numbers in the order of 1, 2, 3, ..., N and pop randomly. You are supposed to tell if a given sequence of numbers is a possible pop sequence of the stack. For example, if M is 5 and N is 7, we can obtain 1, 2, 3, 4, 5, 6, 7 from the stack, but not 3, 2, 1, 7, 5, 6, 4.

Input Specification:


Each input file contains one test case. For each case, the first line contains 3 numbers (all no more than 1000): M (the maximum capacity of the stack), N (the length of push sequence), and K (the number of pop sequences to be checked). Then K lines follow, each contains a pop sequence of N numbers. All the numbers in a line are separated by a space.

Output Specification:


For each pop sequence, print in one line "YES"if it is indeed a possible pop sequence of the stack, or "NO"if not.

Sample Input:

5 7 5
1 2 3 4 5 6 7
3 2 1 7 5 6 4
7 6 5 4 3 2 1
5 6 4 3 7 2 1
1 7 6 5 4 3 2

Sample Output:

YES
NO
NO
YES
NO

아이디어:
하나의 수 N, pop 이전에 1~N은push로 창고에 들어가야 합니다. 이때 창고가 넘쳤는지, 그리고 출력 순서가 정확한지 판단해야 합니다.
 
PS: 테스트 데이터 세트를 제공하는데 처음에 이런 상황을 고려하지 않고 flag 판단을 하지 않았기 때문에 통과할 수 없습니다: (
    4 6 1
    3 1 2 6 5 4
 
#include
#include
#define MaxSize 1003
typedef int Data[MaxSize];
typedef struct SNode* PtrtoSNode;
typedef PtrtoSNode Stack;
struct SNode {
	int top;
	int size;
	Data seq;
};
int Push(Stack S,int a) {
	if(S->topsize) {
		S->seq[S->top++]=a;
		return 1;
	}
	else return 0;
}
int pop(Stack S) {
	if(S->top)
		return S->seq[--S->top];
	else return 0;
}
int main() {
	int M,N,K,i,j,temp,now,flag;
	Stack S=(Stack)malloc( sizeof(struct SNode) );
	scanf("%d %d %d",&M,&N,&K);
	S->size=M;
	//freopen("d:\\result.txt","w",stdout);
	for(i=0;itop=0;
		now=1;
		flag=1;
		for(j=0;j

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