데이터 구조 운동회 점수 통계 실습 보고서 소스 코드
2458 단어 데이터 구조
#include
#include
int n,m,w;
struct Student
{
char name[20];
int mingci;
int score;
};
struct Xiangmu
{
int bianhao;
char xiangname[20];
Student students[50];
int xiangscore;
};
struct School
{
char xiaoname[20];
int renshu;
int Sumnamtuan;
int Sumnvtuan;
int sumtuan;
int sumnanscore;
int sumnvscore;
Xiangmu SuoyouXiangmu[50];
}xuexiao[50];
void shuruchengji(int i)
{
int qumingcishu = ( (i&1)==1?5:3 );
printf(" %d
%d
",i,qumingcishu);
printf(" , ( ), ,
");
char sss[20];int xiaohao,defen;
int j=1;
for(;j<=qumingcishu;j++){
scanf("%s%d%d",sss,&xiaohao,&defen);
xuexiao[xiaohao].SuoyouXiangmu[i].students[j].mingci=j;
strcpy(xuexiao[xiaohao].SuoyouXiangmu[i].students[j].name,sss);
xuexiao[xiaohao].SuoyouXiangmu[i].students[j].score=defen;
}
}
void shuchuxiangchengjidan(int k)
{
printf("%d
",k);
for(int i=1;i<=m+w;i++){
printf(" %d
",i);
for(int j=1;j<=5;j++){
if(xuexiao[k].SuoyouXiangmu[i].students[j].mingci!=0){
printf(" %d %s %d
",
xuexiao[k].SuoyouXiangmu[i].students[j].mingci,
xuexiao[k].SuoyouXiangmu[i].students[j].name,
xuexiao[k].SuoyouXiangmu[i].students[j].score);
if(i<=m){
xuexiao[k].Sumnamtuan+=xuexiao[k].SuoyouXiangmu[i].students[j].score;
}
else
xuexiao[k].Sumnvtuan+=xuexiao[k].SuoyouXiangmu[i].students[j].score;
}
}
}
}
void shuchutuantibiao(int k)
{
printf("
%d
",k);
printf(" %d
",xuexiao[k].Sumnamtuan);
printf(" %d
",xuexiao[k].Sumnvtuan);
printf(" %d
",xuexiao[k].Sumnvtuan+xuexiao[k].Sumnamtuan);
}
int main()
{
int nanzirenshu,nvzirenshu;
printf(" n
");scanf("%d",&n);
printf(" m
");scanf("%d",&m);
printf(" w
");scanf("%d",&w);
for(int i=1;i<=m+w;i++)
shuruchengji(i);
for(int i=1;i<=n;i++)
shuchuxiangchengjidan(i);
for(int i=1;i<=n;i++)
shuchutuantibiao(i);
return 0;
}