한 번 발생하는 일반적인 단어 계산

/**
 * @param {string[]} words1
 * @param {string[]} words2
 * @return {number}
 */
var countWords = function (words1, words2) {
  let mapW1 = new Map();
  let mapW2 = new Map();

  for (let i = 0; i < words1.length; i++) {
    if (mapW1.has(words1[i])) {
      mapW1.set(words1[i], mapW1.get(words1[i] + 1));
    } else {
      mapW1.set(words1[i], 1);
    }
  }

  for (let i = 0; i < words2.length; i++) {
    if (mapW2.has(words2[i])) {
      mapW2.set(words2[i], mapW2.get(words2[i] + 1));
    } else {
      mapW2.set(words2[i], 1);
    }
  }
  let count = 0;

  for (let i = 0; i < words1.length; i++) {
    console.log(words1[i]);
    if (
      mapW1.has(words1[i]) &&
      mapW2.has(words1[i]) &&
      mapW1.get(words1[i]) === 1 &&
      mapW2.get(words1[i]) === 1
    ) {
      count++;
    }
  }
  return count;
};

console.log(
  countWords(
    ["leetcode", "is", "amazing", "as", "is"],
    ["amazing", "leetcode", "is"]
  )
);