Codeforces Round #274 (Div. 2) ——A、Expression

A. Expression
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output
Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers a, b, c on the blackboard. The task was to insert signs of operations '+' and '*', and probably brackets between the numbers so that the value of the resulting expression is as large as possible. Let's consider an example: assume that the teacher wrote numbers 1, 2 and 3 on the blackboard. Here are some ways of placing signs and brackets:
1+2*3=7
1*(2+3)=5
1*2*3=6
(1+2)*3=9
Note that you can insert operation signs only between a and b, and between b and c, that is, you cannot swap integers. For instance, in the given sample you cannot get expression (1+3)*2.
It's easy to see that the maximum value that you can obtain is 9.
Your task is: given a, b and c print the maximum value that you can get.
Input
The input contains three integers a, b and c, each on a single line (1 ≤ a, b, c ≤ 10).
Output
Print the maximum value of the expression that you can obtain.
Sample test(s)
input

1
2
3

output

9

input

2
10
3

output

60

	  ，        ，， :-(

	     。。

	
#include <stdio.h>

int main()
{
	int i, a, b, c;
	int d[6], max;
	scanf("%d %d %d", &a, &b, &c);
	d[0] = a + b + c;
	d[1] = a + b * c;
	d[2] = (a + b) * c;
	d[3] = a * (b + c);
	d[4] = a * b + c;
	d[5] = a * b * c;
	max=d[0];
	for(i=1; i<6; i++)
	{
		if(max<d[i])max=d[i];
	}
	printf("%d
", max);
	return 0;
}