87 - Are they the "same"?
Q.
Given two arrays a and b write a function comp(a, b) (orcompSame(a, b)) that checks whether the two arrays have the "same" elements, with the same multiplicities. "Same" means, here, that the elements in b are the elements in a squared, regardless of the order.
Examples
Valid arrays
a = [121, 144, 19, 161, 19, 144, 19, 11]
b = [121, 14641, 20736, 361, 25921, 361, 20736, 361]
comp(a, b) returns true because in b 121 is the square of 11, 14641 is the square of 121, 20736 the square of 144, 361 the square of 19, 25921 the square of 161, and so on. It gets obvious if we write b's elements in terms of squares:
a = [121, 144, 19, 161, 19, 144, 19, 11]
b = [1111, 121121, 144144, 1919, 161161, 1919, 144144, 1919]
Invalid arrays
If, for example, we change the first number to something else, comp may not return true anymore:
a = [121, 144, 19, 161, 19, 144, 19, 11]
b = [132, 14641, 20736, 361, 25921, 361, 20736, 361]
comp(a,b) returns false because in b 132 is not the square of any number of a.
a = [121, 144, 19, 161, 19, 144, 19, 11]
b = [121, 14641, 20736, 36100, 25921, 361, 20736, 361]
comp(a,b) returns false because in b 36100 is not the square of any number of a.
Remarks
a or b might be [] or {} (all languages except R, Shell).
a or b might be nil or null or None or nothing (except in C++, Elixir, Haskell, PureScript, Pascal, R, Rust, Shell).
If a or b are nil (or null or None, depending on the language), the problem doesn't make sense so return false.
Note for C
The two arrays have the same size (> 0) given as parameter in function comp.
A)
function comp(array1, array2){
//your code here
if (!Array.isArray(array1) || !Array.isArray(array2)) return false
array1.sort((a,b) => a-b)
array2.sort((a,b) => a-b)
array2 = array2.map(el => Math.sqrt(el))
for (let i = 0; i < array1.length; i++) {
if (array1[i] !== array2[i]) return false
}
return true
}
Author And Source
이 문제에 관하여(87 - Are they the "same"?), 우리는 이곳에서 더 많은 자료를 발견하고 링크를 클릭하여 보았다
https://velog.io/@developerjhp/알고리즘-87-Are-they-the-same
저자 귀속: 원작자 정보가 원작자 URL에 포함되어 있으며 저작권은 원작자 소유입니다.
우수한 개발자 콘텐츠 발견에 전념
(Collection and Share based on the CC Protocol.)
function comp(array1, array2){
//your code here
if (!Array.isArray(array1) || !Array.isArray(array2)) return false
array1.sort((a,b) => a-b)
array2.sort((a,b) => a-b)
array2 = array2.map(el => Math.sqrt(el))
for (let i = 0; i < array1.length; i++) {
if (array1[i] !== array2[i]) return false
}
return true
}
Author And Source
이 문제에 관하여(87 - Are they the "same"?), 우리는 이곳에서 더 많은 자료를 발견하고 링크를 클릭하여 보았다 https://velog.io/@developerjhp/알고리즘-87-Are-they-the-same저자 귀속: 원작자 정보가 원작자 URL에 포함되어 있으며 저작권은 원작자 소유입니다.
우수한 개발자 콘텐츠 발견에 전념 (Collection and Share based on the CC Protocol.)