스파르타 코딩클럽 개발일지 4주차 숙제
----------------- <app.py> -----------------------------------------------
from flask import Flask, render_template, jsonify, request
app = Flask(name)
from pymongo import MongoClient
client = MongoClient('localhost', 27017)
db = client.dbhomework
HTML 화면 보여주기
@app.route('/')
def homework():
return render_template('index.html')
주문하기(POST) API
@app.route('/order', methods=['POST'])
def save_order():
name_receive = request.form['name_give']
count_receive = request.form['count_give']
address_receive = request.form['address_give']
phone_receive = request.form['phone_give']
doc = {
'name': name_receive,
'count': count_receive,
'address': address_receive,
'phone': phone_receive
}
db.orders.insert_one(doc)
return jsonify({'result': 'success', 'msg': '주문 완료!'})
주문 목록보기(Read) API
@app.route('/order', methods=['GET'])
def view_orders():
orders = list(db.orders.find({}, {'_id': False}))
return jsonify({'result': 'success', 'orders': orders})
if name == 'main':
app.run('0.0.0.0', port=5000, debug=True)
----------------- <index.html> ---------------------------------------------
```html
<!-- Bootstrap CSS -->
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0/css/bootstrap.min.css"
integrity="sha384-Gn5384xqQ1aoWXA+058RXPxPg6fy4IWvTNh0E263XmFcJlSAwiGgFAW/dAiS6JXm" crossorigin="anonymous">
<!-- Optional JavaScript -->
<!-- jQuery first, then Popper.js, then Bootstrap JS -->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.12.9/umd/popper.min.js"
integrity="sha384-ApNbgh9B+Y1QKtv3Rn7W3mgPxhU9K/ScQsAP7hUibX39j7fakFPskvXusvfa0b4Q"
crossorigin="anonymous"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0/js/bootstrap.min.js"
integrity="sha384-JZR6Spejh4U02d8jOt6vLEHfe/JQGiRRSQQxSfFWpi1MquVdAyjUar5+76PVCmYl"
crossorigin="anonymous"></script>
<title>스파르타코딩클럽 | 부트스트랩 연습하기</title>
<link href="https://fonts.googleapis.com/css2?family=Jua&display=swap" rel="stylesheet">
<style>
* {
font-family: 'Jua', sans-serif;
}
.item-img {
width: 500px;
height: 300px;
background-image: url("https://t1.daumcdn.net/liveboard/nts/5bcccfbd33da4865817b9c606b6b852e.JPG");
background-position: center;
background-size: cover;
}
.price {
font-size: 20px;
}
.item-desc {
width: 500px;
margin-top: 20px;
margin-bottom: 20px;
}
.item-order {
width: 500px;
margin-bottom: 50px;
}
.btn-order {
margin: auto;
width: 100px;
display: block;
}
.wrap {
width: 500px;
margin: auto;
}
.rate {
color: blue;
}
</style>
<script>
$(document).ready(function () {
get_rate();
listing();
});
function listing() {
$.ajax({
type: "GET",
url: "/order",
data: {},
success: function (response) {
if (response["result"] == "success") {
let orders = response['orders'];
for (let i = 0; i < orders.length; i++) {
let name = orders[i]['name'];
let count = orders[i]['count'];
let address = orders[i]['address'];
let phone = orders[i]['phone'];
let temp_html = `<tr>
<th scope="row">${name}</th>
<td>${count}</td>
<td>${address}</td>
<td>${phone}</td>
</tr>`
$('#orders-box').append(temp_html)
}
}
}
})
}
function get_rate() {
$.ajax({
type: "GET",
url: "https://api.manana.kr/exchange/rate.json",
data: {},
success: function (response) {
let now_rate = response[1]['rate'];
$('#now-rate').text(now_rate);
}
})
}
function order() {
let name = $('#order-name').val();
let count = $('#order-count').val();
let address = $('#order-address').val();
let phone = $('#order-phone').val();
$.ajax({
type: "POST",
url: "/order",
data: {name_give: name, count_give: count, address_give: address, phone_give: phone},
success: function (response) {
if (response["result"] == "success") {
alert(response["msg"]);
window.location.reload();
}
}
})
}
</script>
양초를 팝니다 가격:3,000원/개
이 양초는 사실 특별한 힘을 지니고 있어요!
달러-원 환율: 1219.15
이름 | 수량 | 주소 | 전화번호 |
---|
Author And Source
이 문제에 관하여(스파르타 코딩클럽 개발일지 4주차 숙제), 우리는 이곳에서 더 많은 자료를 발견하고 링크를 클릭하여 보았다 https://velog.io/@enfermera/스파르타-코딩클럽-개발일지-4주차-숙제저자 귀속: 원작자 정보가 원작자 URL에 포함되어 있으며 저작권은 원작자 소유입니다.
우수한 개발자 콘텐츠 발견에 전념 (Collection and Share based on the CC Protocol.)