더블 정밀도 문제를 해결합니다.

package com.karl.test;



import java.math.BigDecimal;



public class Arith {

    private static final int DEF_DIV_SCALE = 10;



    private Arith() {

    }



    public static double add(double v1, double v2) {

        BigDecimal b1 = new BigDecimal(Double.toString(v1));

        BigDecimal b2 = new BigDecimal(Double.toString(v2));

        return b1.add(b2).doubleValue();

    }



    public static double sub(double v1, double v2) {

        BigDecimal b1 = new BigDecimal(Double.toString(v1));

        BigDecimal b2 = new BigDecimal(Double.toString(v2));

        return b1.subtract(b2).doubleValue();

    }



    public static double mul(double v1, double v2) {

        BigDecimal b1 = new BigDecimal(Double.toString(v1));

        BigDecimal b2 = new BigDecimal(Double.toString(v2));

        return b1.multiply(b2).doubleValue();

    }



    public static double div(double v1, double v2) {

        return div(v1, v2, DEF_DIV_SCALE);

    }



    public static double div(double v1, double v2, int scale) {

        if (scale < 0) {

            throw new IllegalArgumentException("The scale must be a positive integer or zero");

        }

        BigDecimal b1 = new BigDecimal(Double.toString(v1));

        BigDecimal b2 = new BigDecimal(Double.toString(v2));

        return b1.divide(b2, scale, BigDecimal.ROUND_HALF_UP).doubleValue();

    }



    public static double round(double v, int scale) {

        if (scale < 0) {

            throw new IllegalArgumentException("The scale must be a positive integer or zero");

        }

        BigDecimal b = new BigDecimal(Double.toString(v));

        BigDecimal one = new BigDecimal("1");

        return b.divide(one, scale, BigDecimal.ROUND_HALF_UP).doubleValue();

    }

}