Simplify Path [LeetCode]

Given an absolute path for a file (Unix-style), simplify it.
For example,path =  "/home/" , =>  "/home" path =  "/a/./b/../../c/" , =>  "/c"
click to show corner cases.
Corner Cases:
 

Did you consider the case where path =  "/../" ?In this case, you should return  "/" .

Another corner case is the path might contain multiple slashes  '/'  together, such as  "/home//foo/" .In this case, you should ignore redundant slashes and return  "/home/foo" .

Summary: Very careful about corner cases, like "/", "/.", "..". 

 1 class Solution {

 2 public:

 3     void handleEntry(vector<string> &path_stack, string path_entry) {

 4         if(path_entry == "..") {

 5             if(path_stack.size() > 0)

 6                 path_stack.pop_back();

 7         }else if (path_entry != ".") 

 8                 path_stack.push_back(path_entry);

 9     }

10     

11     string simplifyPath(string path) {

12         string simple_path;

13         if(path.size() == 0)

14             return simple_path;

15         vector<string> path_stack;

16         string path_entry;

17         for(int i = 0; i < path.size(); i ++) {

18             if(path_entry.size() == 0 && path[i] == '/'){

19                 continue;

20             }else if (path_entry.size() != 0 && path[i] == '/') {

21                 handleEntry(path_stack, path_entry);

22                 path_entry.clear();

23             }else {

24                 path_entry.push_back(path[i]);

25             }

26         }

27         if(path_entry.size() > 0)

28             handleEntry(path_stack, path_entry);

29     

30         for(string item: path_stack) {

31             simple_path += "/";

32             simple_path += item;

33         }

34         if(simple_path.size() == 0)

35             return "/";

36         return simple_path;

37     }

38 };