Python: 복잡한dict/json 귀속 처리 (키가 존재하는지, 필드를 삭제하고 정렬하는지 판단)
2224 단어 파이썬 스크립트 프로그래밍
# json/dict
def dict_ordered(obj):
if isinstance(obj, dict):
return sorted((k, dict_ordered(v)) for k, v in obj.items())
if isinstance(obj, list):
return sorted(dict_ordered(x) for x in obj)
else:
return obj
# json/dict
def dict_del(key,obj):
if isinstance(obj, dict):
if key in obj:
obj.pop(key)
for k, v in obj.items():
dict_del(key,v)
if isinstance(obj, list):
for x in obj:
dict_del(key,x)
else:
pass
return obj
# json/dict key
def dict_has_key(key,obj):
if isinstance(obj, dict):
for k, v in obj.items():
if k == key:
return True
else:
ret = dict_has_key(key,v)
if ret:
return True
elif isinstance(obj, list):
for x in obj:
ret = dict_has_key(key,x)
if ret:
return True
else:
pass
if __name__ == '__main__':
tester = {
"base_config":{
"enforce":{
"value":"0",
"inherit":"0",
"global":"0"
},
"modify":{
"value":"0",
"inherit":"0",
"global":"0"
}
},
"safe_control_list":{
"list":[
{
"gid":"0",
"gname":" ",
"isactive":"1",
"rule_id":"0",
"rule_name":" ",
"time_range":" ",
"time_range_id":"1",
"policy_tpl":"33",
"policy_tpl_id":"17",
"isonline":"3",
"priority":"1"
}
]
}
}
print(dict_has_key("rule_id",tester))
print(dict_del("policy_tpl_id",tester))
print(dict_ordered(tester))