PAT(Advanced Level) Practice 1001 A+B Format(20점)

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1001 A+B 포맷(20점)


Calculate a + b a+b a+b and output the sum in standard format – that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input Specification:


Each input file contains one test case. Each case contains a pair of integers a a a and b b b where − 1 0 6 < = a , b < = 1 0 6 −10^6<=a, b<=10^6 −106<=a,b<=106​​ . The numbers are separated by a space.

Output Specification:


For each test case, you should output the sum of a a a and b b b in one line. The sum must be written in the standard format.

Sample Input:

1000000 9

Sample Output:

999,991

My code:
#include 
#include 
#include 

char* g(char *a)
{
    int p = strlen(a);
    char *b;
    b = (char*)malloc(sizeof(char)*20);
    
    for (int i=0;i<20;i++){
        b[i] = 0;
    }
    
    for (int i=0;i<p;i++){
        b[p-i-1] = a[i];
    }
    return b;
}
char* f(int c)
{
    char *str;
    str = (char*)malloc(sizeof(char)*20);
    for (int i=0;i<20;i++){
        str[i] = 0;
    }
    int index = 0;
    while(1){
        int tmp = c%10;
        c = c/10;
        str[index] = tmp+'0';
        index++;
        if(c==0)break;
    }
    return g(str);
}

int main(void)
{
    char *re;
    re = (char*)malloc(sizeof(char)*20);
    for (int i=0;i<20;i++){
        re[i] = 0;
    }
    
    int a,b;
    scanf("%d %d",&a, &b);
    int c = a+b;
    int sign=0;
    if (c<0){
        sign=1;
        c = -c;
    }
    
    re = f(c);
    if (sign==1)printf("-");
    int index = 0;
    int q = strlen(re);
    while (re[index]!=0){
        if (index>0 && (q-index)%3==0){
            printf(",");
        }
        printf("%d",re[index]-'0');
        index++;
    }
	
	free(re);
    return 0;
}

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