목록 파이썬
Python의 목록 목록은 목록의 각 요소 자체가 목록임을 의미합니다. 목록에는 목록이 요소로 포함되어 있습니다.
내용의 테이블
Python에서 목록 목록을 만드는 방법은 무엇입니까?
To Enclose multiple lists as an item inside square brackets.
Suppose to create a nested list to add all lists as elements inside a list.
a = [1,2,3],b = [3,4,5],c = [6,7,8] => list_of_list [[1,2,3], [3,4,5], [6,7,8]]
Python의 단일 목록에서 목록 목록을 만드는 방법은 무엇입니까?
Use the abstract syntax Trees to convert the single list into a list of lists in python (Nested List)
import ast
# List Initialization
list1 = ['1 , 2', '7 , 9', '34 , 98', '66 , 89347', '723, 54, 0']
# using ast to convert
ListOfLists = [list(ast.literal_eval(x)) for x in list1]
# printing
print(ListOfLists)
Output
[[1, 2], [7, 9], [34, 98], [66, 89347], [723, 54, 0]]
목록 목록을 생성하는 방법
● Define blank list
● Define the range of the list of lists (item) from 0 to 3
● Create a sub-list inside every nested list of range from 1 to 5
● Print
listoflists = []
for i in range(0,3):
sublist = []
for j in range(1,5):
sublist.append((i,j))
listoflists.append(sublist)
print (listoflists)
Output
[[(0, 1), (0, 2), (0, 3), (0, 4)], [(1, 1), (1, 2), (1, 3), (1, 4)], [(2, 1), (2, 2), (2, 3), (2, 4)]]
여러 목록을 목록 목록으로 변환하는 방법
Call the multiple lists inside the square brackets with lists name that will embed the multiple lists into a lists
list1=[1,2]
list2=[3,4]
list3=[4,5,6]
print("List 1:" +str(list1))
print("List 2:" +str(list2))
print("List 3:" +str(list3))
listoflists=[list1, list2, list3]
print ("List of lists"+str(listoflists))
Output
List 1:[1, 2]
List 2:[3, 4]
List 3:[4, 5, 6]
List of lists[[1, 2], [3, 4], [4, 5, 6]]
목록 목록을 NumPy 배열로 변환하는 방법
Import NumPy library that converts a list of lists into a 2-Dimensional array in Python.
# Import the NumPy library
import numpy as nmp
# Create the list of lists
list_of_lists = [['x', 'y', 'z'], [4, 5, 6], [7, 8, 9]]
# Convert it to an array
arr = nmp.array(list_of_lists)
# Print as array
print(arr)
output
[['x' 'y' 'z']
['4' '5' '6']
['7' '8' '9']]
파이썬에서 목록 목록을 문자열로 변환하는 방법
● Define the lists of characters in a list
● Use the join method that connects each character of a defined list
● Map the two lists as two words
# Convert List of lists to Strings
a= [["M", "y"],["C", "o", "d", "e"]]
res = list(map(''.join, a))
print(*res, sep=" ")
output
My Code
파이썬에서 설정할 목록 목록으로 변환하는 방법
● Use the map method with a set function that removes duplicate items from the list.
● print list of lists as set in python.
# Convert List of lists to Set
a= [[1,2,3,4],["a", "a", "b", "e"],["Sam", "John"]]
res = list(map(set,a))
print(*res, sep=" ")
Output
{1, 2, 3, 4} {'b', 'a', 'e'} {'Sam', 'John'}
Python에서 목록 목록으로 설정을 변환하는 방법
● Use the comprehension method that iterates each object of the set sequentially
● Use “list” to convert a defined set into a list
● n defined the number of nested lists.
● Print a Python list of lists with the help of the comprehension method.
my_set = set({1, 4, 2, 3, 5, 6, 7, 8,})
l = list(my_set)
n = 3
# using list comprehension
x = [l[i:i + n] for i in range(0, len(l), n)]
print(x)
Output
[[1, 2, 3], [4, 5, 6], [7, 8]]
파이썬에서 목록 목록을 튜플 목록으로 변환하는 방법
Tuples stores data in an ordered form.
● Use map function with built-in tuple method to convert the list of lists into tuple in python.
a= [[1,2,3,4],["a", "a", "b", "e"],["Sam", "John", "Morgan"]]
tuples = list(map(tuple, a))
print(tuples)
output
[(1, 2, 3, 4), ('a', 'a', 'b', 'e'), ('Sam', 'John', 'Morgan')]
Python에서 튜플 목록을 목록 목록으로 변환하는 방법은 무엇입니까?
Perform the reverse operation to convert tuples into the list of lists.
● Use the built-in list function to convert a list of tuples into a list of lists.
● For loop iterate each element of tuple and print as a nested list.
tuples = [(1, 2, 3), (4, 5, 6), (90, 376, 84)]
lists = [list(a) for a in tuples]
print(lists)
output
[[1, 2, 3], [4, 5, 6], [90, 376, 84]]
Python에서 목록 목록을 Dataframe으로 변환하는 방법
DataFrame is a labeled data structure that is 2-Dimensional. It contains columns and rows that may contain different data types inside it.
● Import Pandas library to convert a list of lists to dataframe.
● Define a list of lists.
● Define columns name with the same length of list items. E.g., 3 columns name for 3 data inside the nested list
● Print as a column labeled data with index number automatically.
import pandas as pd
data = [['DSA', 'Python', 80],
['DS', 'MATLAB', 70],
['OSDC', 'C', 94],
['MAPD', 'JAVA', 78]]
df = pd.DataFrame(data, columns=['Subject', 'Language', 'Marks'])
print(df)
Output
Subject Language Marks
0 DSA Python 80
1 DS MATLAB 70
2 OSDC C 94
3 MAPD JAVA 78
DataFrame을 목록 목록으로 변환하는 방법
Perform the reverse function to convert the dataframe into the list of lists by using a built-in list function .
import pandas as pd
df = pd.DataFrame(
[['DSA', 'Python', 80],
['DS', 'MATLAB', 70],
['OSDC', 'C', 94],
['MAPD', 'JAVA', 78]], columns= ['Subject', 'Language', 'Marks'])
print ("DataFrame Output")
print(df)
def dfToTable(df:pd.DataFrame) -> list:
return [list(df.columns)] + df.values.tolist()
print("\n Convert DataFrame to list of lists :" +str(dfToTable(df)))
output
DataFrame Output
Subject Language Marks
0 DSA Python 80
1 DS MATLAB 70
2 OSDC C 94
3 MAPD JAVA 78
Convert DataFrame to list of lists :[['Subject', 'Language', 'Marks'], ['DSA', 'Python', 80], ['DS', 'MATLAB', 70], ['OSDC', 'C', 94], ['MAPD', 'JAVA', 78]]
Python에서 목록 목록을 사전으로 변환하는 방법
Dictionary contains keys with their values in ordered form without duplication.
● Define a list of lists
● Use for loop to iterate key with index 0 and value with index 1 and print as a dictionary
a = [['samsung', 1],['OPPO', 3],['iPhone', 2], ['Huawei', 4]]
data_dict = {}
for x in a:
data_dict[x[0]] = x[1]
print(data_dict)
Output
{'samsung': 1, 'OPPO': 3, 'iPhone': 2, 'Huawei': 4}
파이썬에서 사전을 목록 목록으로 변환하는 방법
● Define the dictionary with key and their values.
● Convert to list of lists with map and list function
dict = {'samsung': 1, 'OPPO': 3, 'iPhone': 2, 'Huawei': 4}
a= list(map(list, dict.items()))
print(a)
Output
[['samsung', 1], ['OPPO', 3], ['iPhone', 2], ['Huawei', 4]]
Python에서 목록 목록 정렬
오름차순으로 목록 목록 정렬
Sort according to the first element of each nested list. It sorts the list according to the first value of each nested list. This method makes changes to the original list itself.
A = [[5, 90], [4, 89], [2, 70], [1, 0]]
print("Orignal List:" +str(A))
A.sort()
print("New sorted list A is: % s" % (A))
*Output *
Orignal List:[[5, 90], [4, 89], [2, 70], [1, 0]]
New sorted list A is: [[1, 0], [2, 70], [4, 89], [5, 90]]
목록 목록을 내림차순으로 정렬
Use reverse sorting order to sort a list of lists in descending manner.
A = [[5, 90], [4, 89], [2, 70], [1, 0]]
print("Orignal List:" +str(A))
A.sort(reverse=True)
print("Descending/reverse sorted list A is: % s" % (A))
*Output *
Orignal List:[[5, 90], [4, 89], [2, 70], [1, 0]]
Descending/reverse sorted list A is: [[5, 90], [4, 89], [2, 70], [1, 0]]
목록 목록을 길이별로 정렬
Sort a list of lists according to the length of each list. “len” function sorts the list with the long length first.
A = [[1, 2, 3, 4],['a', 'b', 'c', 'd'],[1, 5, 6, 'f', 'a']]
A.sort(key=len)
print(A)
output
[[1, 2, 3, 4], ['a', 'b', 'c', 'd'], [1, 5, 6, 'f', 'a']]
목록 목록의 작업
목록의 Python Zip 목록
Define three lists and zipped them into a list of lists with the help of the zip method
Domain = ['Software', 'Networking', 'Telecommunication']
Students = [8345, 8437, 422]
Companies = ['Microsoft', 'CISCO', 'AT&T']
zipped = zip(Domain, Students, Companies)
print(list(zipped))
Output
[('Software', 8345, 'Microsoft'), ('Networking', 8437, 'CISCO'), ('Telecommunication', 422, 'AT&T')]
Python 목록 목록 풀기
Use for loop with map and join function to unpack the zipped list of lists.
members= [('Software', 8345, 'Microsoft'), ('Networking', 8437, 'CISCO'), ('Telecommunication', 422, 'AT&T')]
for item in members:
print (' '.join(map(str, item)))
*Output *
Software 8345 Microsoft
Networking 8437 CISCO
Telecommunication 422 AT&T
In [ ]:
Python의 목록 목록 바꾸기
This method transposes the array to a list with the help of the NumPy library. This method changes the fashion of the array by taking 1st element of each list into 1st list, 2nd element of each array into the 2nd list, and 3rd element of each array into 3rd list in the output.
import numpy as np
l = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
b= np.array(l).T.tolist()
print(b)
Output
[[1, 4, 7], [2, 5, 8], [3, 6, 9]]
파이썬에서 목록 목록 추가
Append is a built-in function of python programming that helps to append the additional sublist inside the list.
list1 = [["apple"], ["banana", "grapes"],["cherry", "guava"]]
AddList = [1, 2, 3]
list1.append(AddList)
print(list1)
Output
[['apple'], ['banana', 'grapes'], ['cherry', 'guava'], [1, 2, 3]]
목록의 하위 목록 내부 항목
To append the additional item inside the list of lists with the help of the index value. e.g., a[2].append(4): append 4 in list number 2. ( index starts from 0)
a= [["apple"], ["banana", "grapes"] ,["cherry", "guava"]]
a[2].append(4)
print(a)
Output
[['apple'], ['banana', 'grapes'], ['cherry', 'guava', 4]]
목록 안에 목록 삽입
Insert take two arguments. insert (position, item)
● the position where the list add. e.g., 2
● The item that adds to the list
a = [[1, 2], [3, 4],[5]]
print(a)
list1=[1, 2]
a.insert(2,list1)
print(a)
Output
[[1, 2], [3, 4], [5]]
[[1, 2], [3, 4], [1, 2], [5]]
목록의 파이썬 목록 확장
Use extend function to extend the number of lists inside a list
a = [['Samsung', 'Apple']]
b = [[6, 0, 4, 1]]
a.extend(b)
print (a)
Output
[['Samsung', 'Apple'], [6, 0, 4, 1]]
In [ ]:
목록의 팝 목록
The pop method removes the item defined item in the index
● Define 3 lists.
● Convert into a list of lists
● Remove item that is on the position of index 1 from that index number is 2
Note: index number starting from 0
list1=[1,2]
list2=[3,4]
list3=[4,5,6]
listoflists=[list1, list2, list3]
print ("Orignal List of lists:"+str(listoflists))
listoflists[2].pop(1)
print ("Popped list:" +str(listoflists))
Output
Orignal List of lists:[[1, 2], [3, 4], [4, 5, 6]]
Popped list:[[1, 2], [3, 4], [4, 6]]
파이썬에서 목록의 연결 목록
Concatenate a list of lists to convert into a single list, using the sum operation.
● Define the list of lists
● Use sum property to concatenate the lists
z = [["a","b"], ["c"], ["d", "e", "f"]]
result = sum(z, [])
print(result)
Output
['a', 'b', 'c', 'd', 'e', 'f']
목록 목록에서 중복 항목 제거
Except “set” property, there is another method that removes the duplicate item from the list of lists
Use gruopby of itertools that will sort the list of lists one by one and remove duplicate nested lists from the list.
import itertools
a = [[5, 8], [4], [5], [5, 6, 2], [1, 2], [3], [4], [5], [3]]
a.sort()
l= list(k for k,_ in itertools.groupby(a))
print(l)
output
[[1, 2], [3], [4], [5], [5, 6, 2], [5, 8]]
대괄호 없이 목록 목록 인쇄
This method converts and prints all the items of the list without square brackets and prints them as comma-separated values.
a=[["Cricket", 2], ["Football",6, 5], ["Tennis", 2], ["Hockey", 2] ]
for item in a:
print(str(item[0:])[1:-1])
output
'Cricket', 2
'Football', 6, 5
'Tennis', 2
'Hockey', 2
In [ ]:
인덱스 번호를 사용하여 목록 목록 호출
To access the particular list inside the list, use the list position as an index when calling the print command.
e.g. x [2]: item 3 of list x (index count start from 0)
x = [["a","b"], ["c"], ["d", "e", "f"]]
print(x[2])
Output
['d', 'e', 'f']
Python의 목록 목록 항목에 대한 액세스
e.g. x [2][1]: element 2 of list 3 of list
x = [["a","b"], ["c"], ["d", "e", "f"]]
print(x[2][1])
Output
e
파이썬에서 목록 목록 삭제
Use del with position index that wants to delete and print a modified list of list.
x = [["a","b"], ["c"], ["d", "e", "f"]]
del x[1]
print(x)
Output
[['a', 'b'], ['d', 'e', 'f']]
결론
In this article, we have tried to cover all the operations such as all types of Sorting of the list of lists, Conversion of the list of lists, deletion, insertion, extension, concatenation, append, etc.
Reference
이 문제에 관하여(목록 파이썬), 우리는 이곳에서 더 많은 자료를 발견하고 링크를 클릭하여 보았다
https://dev.to/aisharajput/list-of-lists-python-359p
텍스트를 자유롭게 공유하거나 복사할 수 있습니다.하지만 이 문서의 URL은 참조 URL로 남겨 두십시오.
우수한 개발자 콘텐츠 발견에 전념
(Collection and Share based on the CC Protocol.)
Domain = ['Software', 'Networking', 'Telecommunication']
Students = [8345, 8437, 422]
Companies = ['Microsoft', 'CISCO', 'AT&T']
zipped = zip(Domain, Students, Companies)
print(list(zipped))
[('Software', 8345, 'Microsoft'), ('Networking', 8437, 'CISCO'), ('Telecommunication', 422, 'AT&T')]
members= [('Software', 8345, 'Microsoft'), ('Networking', 8437, 'CISCO'), ('Telecommunication', 422, 'AT&T')]
for item in members:
print (' '.join(map(str, item)))
Software 8345 Microsoft
Networking 8437 CISCO
Telecommunication 422 AT&T
In [ ]:
import numpy as np
l = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
b= np.array(l).T.tolist()
print(b)
[[1, 4, 7], [2, 5, 8], [3, 6, 9]]
list1 = [["apple"], ["banana", "grapes"],["cherry", "guava"]]
AddList = [1, 2, 3]
list1.append(AddList)
print(list1)
[['apple'], ['banana', 'grapes'], ['cherry', 'guava'], [1, 2, 3]]
a= [["apple"], ["banana", "grapes"] ,["cherry", "guava"]]
a[2].append(4)
print(a)
[['apple'], ['banana', 'grapes'], ['cherry', 'guava', 4]]
● the position where the list add. e.g., 2
● The item that adds to the list
a = [[1, 2], [3, 4],[5]]
print(a)
list1=[1, 2]
a.insert(2,list1)
print(a)
[[1, 2], [3, 4], [5]]
[[1, 2], [3, 4], [1, 2], [5]]
a = [['Samsung', 'Apple']]
b = [[6, 0, 4, 1]]
a.extend(b)
print (a)
[['Samsung', 'Apple'], [6, 0, 4, 1]]
In [ ]:
● Define 3 lists.
● Convert into a list of lists
● Remove item that is on the position of index 1 from that index number is 2
Note: index number starting from 0
list1=[1,2]
list2=[3,4]
list3=[4,5,6]
listoflists=[list1, list2, list3]
print ("Orignal List of lists:"+str(listoflists))
listoflists[2].pop(1)
print ("Popped list:" +str(listoflists))
Orignal List of lists:[[1, 2], [3, 4], [4, 5, 6]]
Popped list:[[1, 2], [3, 4], [4, 6]]
● Define the list of lists
● Use sum property to concatenate the lists
z = [["a","b"], ["c"], ["d", "e", "f"]]
result = sum(z, [])
print(result)
['a', 'b', 'c', 'd', 'e', 'f']
Use gruopby of itertools that will sort the list of lists one by one and remove duplicate nested lists from the list.
import itertools
a = [[5, 8], [4], [5], [5, 6, 2], [1, 2], [3], [4], [5], [3]]
a.sort()
l= list(k for k,_ in itertools.groupby(a))
print(l)
[[1, 2], [3], [4], [5], [5, 6, 2], [5, 8]]
a=[["Cricket", 2], ["Football",6, 5], ["Tennis", 2], ["Hockey", 2] ]
for item in a:
print(str(item[0:])[1:-1])
'Cricket', 2
'Football', 6, 5
'Tennis', 2
'Hockey', 2
In [ ]:
e.g. x [2]: item 3 of list x (index count start from 0)
x = [["a","b"], ["c"], ["d", "e", "f"]]
print(x[2])
['d', 'e', 'f']
x = [["a","b"], ["c"], ["d", "e", "f"]]
print(x[2][1])
e
x = [["a","b"], ["c"], ["d", "e", "f"]]
del x[1]
print(x)
[['a', 'b'], ['d', 'e', 'f']]
Reference
이 문제에 관하여(목록 파이썬), 우리는 이곳에서 더 많은 자료를 발견하고 링크를 클릭하여 보았다 https://dev.to/aisharajput/list-of-lists-python-359p텍스트를 자유롭게 공유하거나 복사할 수 있습니다.하지만 이 문서의 URL은 참조 URL로 남겨 두십시오.
우수한 개발자 콘텐츠 발견에 전념 (Collection and Share based on the CC Protocol.)