LeetCode 두 갈래 트리 반복 반복 실현(전순, 중순, 후순)
2512 단어 LeetCode
앞차례 를 두루 다니다
https://leetcode-cn.com/problems/binary-tree-preorder-traversal/description/
1. 루트 노드에 먼저 액세스
2. 왼쪽 트리 다시 방문하기
3. 마지막으로 오른쪽 트리를 방문한다/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector preorderTraversal(TreeNode* root) {
vector ret;
inorderTraversal(root, ret);
return ret;
}
private:
void preorderTraversal(TreeNode* pNode, vector& ret){
if(pNode){
ret.push_back(pNode->val);
inoderTraversal(pNode->left, ret);
inoderTraversal(pNode->right, ret);
}
}
};
중서 역행
https://leetcode-cn.com/problems/binary-tree-inorder-traversal/description/
1. 왼쪽 트리 먼저 방문하기
2. 루트 노드 재방문
3. 마지막으로 오른쪽 트리를 방문한다/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector inorderTraversal(TreeNode* root) {
vector ret;
inorderTraversal(root, ret);
return ret;
}
private:
void inorderTraversal(TreeNode* pNode, vector& ret){
if(pNode){
inorderTraversal(pNode->left, ret);
ret.push_back(pNode->val);
inorderTraversal(pNode->right, ret);
}
}
};
뒤돌아 다니다
https://leetcode-cn.com/problems/binary-tree-postorder-traversal/description/
1. 먼저 왼쪽 나무를 훑어보다
2. 다시 우자나무를 훑어보다
3. 마지막으로 루트 노드를 반복/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector postorderTraversal(TreeNode* root) {
vector ret;
postoderTraversal(root, ret);
return ret;
}
private:
void postorderTraversal(TreeNode* pNode, vector& ret){
if(pNode){
postoderTraversal(pNode->left, ret);
postoderTraversal(pNode->right,ret);
ret.push_back(pNode->val);
}
}
};
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector preorderTraversal(TreeNode* root) {
vector ret;
inorderTraversal(root, ret);
return ret;
}
private:
void preorderTraversal(TreeNode* pNode, vector& ret){
if(pNode){
ret.push_back(pNode->val);
inoderTraversal(pNode->left, ret);
inoderTraversal(pNode->right, ret);
}
}
}; https://leetcode-cn.com/problems/binary-tree-inorder-traversal/description/
1. 왼쪽 트리 먼저 방문하기
2. 루트 노드 재방문
3. 마지막으로 오른쪽 트리를 방문한다
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector inorderTraversal(TreeNode* root) {
vector ret;
inorderTraversal(root, ret);
return ret;
}
private:
void inorderTraversal(TreeNode* pNode, vector& ret){
if(pNode){
inorderTraversal(pNode->left, ret);
ret.push_back(pNode->val);
inorderTraversal(pNode->right, ret);
}
}
}; 뒤돌아 다니다
https://leetcode-cn.com/problems/binary-tree-postorder-traversal/description/
1. 먼저 왼쪽 나무를 훑어보다
2. 다시 우자나무를 훑어보다
3. 마지막으로 루트 노드를 반복/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector postorderTraversal(TreeNode* root) {
vector ret;
postoderTraversal(root, ret);
return ret;
}
private:
void postorderTraversal(TreeNode* pNode, vector& ret){
if(pNode){
postoderTraversal(pNode->left, ret);
postoderTraversal(pNode->right,ret);
ret.push_back(pNode->val);
}
}
};
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector postorderTraversal(TreeNode* root) {
vector ret;
postoderTraversal(root, ret);
return ret;
}
private:
void postorderTraversal(TreeNode* pNode, vector& ret){
if(pNode){
postoderTraversal(pNode->left, ret);
postoderTraversal(pNode->right,ret);
ret.push_back(pNode->val);
}
}
};