Leet Code OJ 258. Add Digits [Difficulty: Easy]

969 단어
제목: Given a non-negative integer num, repeatedly add all its digits until the result has only one digit.
For example:
Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it.
Follow up: Could you do it without any loop/recursion in O(1) runtime?
코드 구현:
public class Solution {
    public int addDigits(int num) {
        if(num>9){
            return addDigits(num%10+addDigits(num/10));
        }else{
            return num;
        }
    }
}

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