【동적 기획 계수】numsdelete

8051 단어 ACM_DP
Ways of transforming one string to other by removing 0 or more characters Given two sequences A, B, find out number of unique ways in sequence A, to form a subsequence of A that is identical to the sequence B. Transformation is meant by converting string A (by removing 0 or more characters) to string B.
Examples:
Input : A = “abcccdf”, B = “abccdf” Output : 3 Explanation : Three ways will be -> “ab.ccdf”, “abc.cdf” & “abcc.df” . “.” is where character is removed.
Input : A = “aabba”, B = “ab” Output : 4 Expalnation : Four ways will be -> “a.b…”, “a…b.”, “.ab…” & “.a.b.” . “.” is where characters are removed.
#include 
#include 
#include 
using namespace std;

int nums_delete(string a, string b) {
    int n = a.length();
    int m = b.length();
    vector<vector<int>> dp(n + 1, vector<int>(m + 1, 0));
    for (int i = 0; i <= n; ++i) {
        dp[i][0] = 1;
    }
    int result = 0;
    for (int i = 1; i <= n; ++i) {
        for(int j = 1; j <= m; ++j) {
            if (a[i - 1] == b[j - 1]) {
                dp[i][j] += dp[i - 1][j - 1];
            }
            dp[i][j] += dp[i - 1][j];
        }
    }
    return dp[n][m];
}

int main() {
    cout << nums_delete("aabba", "ab") << endl;
    cout << nums_delete("abcccdf", "abccdf") << endl;
	return 0;
}

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