동적 계획 1002

2074 단어
제목:
Problem Description
A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = <x1, x2, ..., xm> another sequence Z = <z1, z2, ..., zk> is a subsequence of X if there exists a strictly increasing sequence <i1, i2, ..., ik> of indices of X such that for all j = 1,2,...,k, xij = zj. For example, Z = <a, b, f, c> is a subsequence of X = <a, b, c, f, b, c> with index sequence <1, 2, 4, 6>. Given two sequences X and Y the problem is to find the length of the maximum-length common subsequence of X and Y.
The program input is from a text file. Each data set in the file contains two strings representing the given sequences. The sequences are separated by any number of white spaces. The input data are correct. For each set of data the program prints on the standard output the length of the maximum-length common subsequence from the beginning of a separate line.

 
Sample Input 

   
   
   
   

    
    
    
    abcfbc abfcab
programming contest 
abcd mnp

 
Sample Output 

   
   
   
   

    
    
    
    4
2
0

코드:
#include <stdio.h>
#include <string.h>
#include <algorithm>
using namespace std;

char s1[1000],s2[1000];
int dp[1000][1000];
int len1,len2;

void LCS()
{
    int i,j;
    memset(dp,0,sizeof(dp));
    for(i = 1; i<=len1; i++)
    {
        for(j = 1; j<=len2; j++)
        {
            if(s1[i-1] == s2[j-1])
                dp[i][j] = dp[i-1][j-1]+1;
            else
                dp[i][j] = max(dp[i-1][j],dp[i][j-1]);
        }
    }
}

int main()
{
    while(~scanf("%s%s",s1,s2))
    {
        len1 = strlen(s1);
        len2 = strlen(s2);
        LCS();
        printf("%d
",dp[len1][len2]);
    }

    return 0;
}

C 언어 를 사용 하여 순환 단일 체인 표를 만 듭 니까?
데이터 구조 -- 거품 정렬 (C 언어)

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