django 조합 검색 (검색 탭 저장 데이터베이스에)

models.py

from __future__ import unicode_literals
from django.db import models

# Create your models here.

class Category(models.Model):
    caption = models.CharField(max_length=12)
    def __unicode__(self):
        return self.caption

class ArticleTag(models.Model):
    caption = models.CharField(max_length=12)
    def __unicode__(self):
        return self.caption

class Article(models.Model):
    title = models.CharField(max_length=32, unique=True)
    content = models.TextField()
    author = models.CharField(max_length=32)
    category = models.ForeignKey(Category)
    article_tag = models.ForeignKey(ArticleTag)
    def __unicode__(self):
        return self.title

urls.py

from django.conf.urls import url
from django.contrib import admin
from app01 import views

urlpatterns = [
    url(r'^admin/', admin.site.urls),
#   <...>       @       _id@ ,       ..objects.update(**kwargs)
    url(r'^index-(?P\d+)-(?P\d+).html', views.index, name='index'),
]

views.py

from django.shortcuts import render
from app01 import models
# Create your views here.

def index(request, *args, **kwargs):
    # print(kwargs)   kwargs     ， {'category_id':'1', 'article_tag_id':'2'}
#     id   0，         
    condition = {}
    for k, v in kwargs.items():
        kwargs[k] = int(v)  #kwargs          ，   v   int  ,   urls.py             ,   category_id      int  
        if v == '0':
            pass          #   0 ，      
        else:
            condition[k] = v   #    0   ..

    categorys = models.Category.objects.all()
    article_tags = models.ArticleTag.objects.all()
    articles = models.Article.objects.filter(**condition)
    return render(request, 'index.html', {'articles': articles, 'categorys': categorys, 'article_tags': article_tags, 'kwargs': kwargs})

tamplate-index.html