Codeforces 659B Qualifying Contest[시뮬레이션]

제목 링크: Codeforces 659B Qualifying Contest
B. Qualifying Contest time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard output Very soon Berland will hold a School Team Programming Olympiad. From each of the m Berland regions a team of two people is invited to participate in the olympiad. The qualifying contest to form teams was held and it was attended by n Berland students. There were at least two schoolboys participating from each of the m regions of Berland. The result of each of the participants of the qualifying competition is an integer score from 0 to 800 inclusive.
The team of each region is formed from two such members of the qualifying competition of the region, that none of them can be replaced by a schoolboy of the same region, not included in the team and who received a greater number of points. There may be a situation where a team of some region can not be formed uniquely, that is, there is more than one school team that meets the properties described above. In this case, the region needs to undertake an additional contest. The two teams in the region are considered to be different if there is at least one schoolboy who is included in one team and is not included in the other team. It is guaranteed that for each region at least two its representatives participated in the qualifying contest.
Your task is, given the results of the qualifying competition, to identify the team from each region, or to announce that in this region its formation requires additional contests.
Input The first line of the input contains two integers n and m (2 ≤ n ≤ 100 000, 1 ≤ m ≤ 10 000, n ≥ 2m) — the number of participants of the qualifying contest and the number of regions in Berland.
Next n lines contain the description of the participants of the qualifying contest in the following format: Surname (a string of length from 1 to 10 characters and consisting of large and small English letters), region number (integer from 1 to m) and the number of points scored by the participant (integer from 0 to 800, inclusive).
It is guaranteed that all surnames of all the participants are distinct and at least two people participated from each of the m regions. The surnames that only differ in letter cases, should be considered distinct.
Output Print m lines. On the i-th line print the team of the i-th region — the surnames of the two team members in an arbitrary order, or a single character “?” (without the quotes) if you need to spend further qualifying contests in the region.
Examples input 5 2 Ivanov 1 763 Andreev 2 800 Petrov 1 595 Sidorov 1 790 Semenov 2 503 output Sidorov Ivanov Andreev Semenov input 5 2 Ivanov 1 800 Andreev 2 763 Petrov 1 800 Sidorov 1 800 Semenov 2 503 output ? Andreev Semenov Note In the first sample region teams are uniquely determined.
In the second sample the team from region 2 is uniquely determined and the team from region 1 can have three teams: “Petrov”-“Sidorov”, “Ivanov”-“Sidorov”, “Ivanov” -“Petrov”, so it is impossible to determine a team uniquely.
제목: n개인과 m개의 종교가 있어 모든 사람의 종교 신앙과 전투력을 제공한다.종교마다 전투력이 가장 높은 두 사람을 뽑는다. 만약 이 두 사람이 유일하게 확실한 것이 아니라면 수출?
AC 코드:

#include <iostream>
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <cmath>
#include <algorithm>
#include <vector>
#include <queue>
#include <map>
#include <stack>
#define PI acos(-1.0)
#define CLR(a, b) memset(a, (b), sizeof(a))
#define fi first
#define se second
#define ll o<<1
#define rr o<<1|1
using namespace std;
typedef long long LL;
typedef pair<int, int> pii;
const int MAXN = 1e5 + 10;
const int pN = 1e6;// <= 10^7
const int INF = 0x3f3f3f3f;
const int MOD = 1e9 + 7;
void add(LL &x, LL y) { x += y; x %= MOD; }
struct Node {
    string name;
    int score, region;
};
Node num[MAXN];
bool cmp(Node a, Node b) {
    return a.region != b.region ? a.region < b.region : a.score > b.score;
}
int main()
{
    int n, m; cin >> n >> m;
    for(int i = 0; i < n; i++) {
        cin >> num[i].name >> num[i].region >> num[i].score;
    }
    sort(num, num+n, cmp); int id = 1;
    for(int i = 1; i < n; i++) {
        if(num[i].region != num[i-1].region) {
            id = 1;
        }
        else {
            ++id;
            if(id == 2 && num[i].region != num[i+1].region) {
                cout << num[i-1].name << ' ' << num[i].name << endl;
                id = 4;
            }
            else if(id == 3) {
                if(num[i].score != num[i-1].score) {
                    cout << num[i-2].name << ' ' << num[i-1].name << endl;
                }
                else {
                    cout << "?" << endl;
                }
            }
        }
    }
    return 0;
}