C# VB 10진수 16진수 간 변환

방법 1:

 
  
int d=10; 
  
d.ToString("x") //  x  Ｘ，，，    １６      ． 
  
int x=Convert.ToInt32(d.ToString("x"),16);／／ １６        １０   ． 
  
 
 

방법2:

 
  
static void Main() 
  
{ 
  
int i = 446; 
  
string hex = i.ToString( "X" /* or x * ); 
  
Console.WriteLine( hex ); 
  
int j = HexToInt( hex ); 
  
Console.WriteLine( j ); 
  
} 
  
static int HexToInt(string hex) 
  
{ 
  
hex = Regex.Replace(hex, "^0x", "", RegexOptions.IgnoreCase); 
  
if (Regex.IsMatch(hex, "[g-z]", RegexOptions.IgnoreCase)) 
  
{ 
  
throw new Exception("Invalid Hexadecimal Expression.: 0x" + hex); 
  
} 
  
char[] chars = hex.ToUpper().ToCharArray(); 
  
Array.Reverse(chars); 
  
int dec = 0; 
  
for (int i = 0; i < chars.Length; i++) 
  
{ 
  
dec += HexMapping(chars[i]) * (int)Math.Pow(16, i); 
  
} 
  
return dec; 
  
} 
  
static int HexMapping(char c) 
  
{ 
  
switch (c) 
  
{ 
  
case '0': 
  
return 0; 
  
case '1': 
  
return 1; 
  
case '2': 
  
return 2; 
  
case '3': 
  
return 3; 
  
case '4': 
  
return 4; 
  
case '5': 
  
return 5; 
  
case '6': 
  
return 6; 
  
case '7': 
  
return 7; 
  
case '8': 
  
return 8; 
  
case '9': 
  
return 9; 
  
case 'A': 
  
return 10; 
  
case 'B': 
  
return 11; 
  
case 'C': 
  
return 12; 
  
case 'D': 
  
return 13; 
  
case 'E': 
  
return 14; 
  
case 'F': 
  
return 15; 
  
default : 
  
throw new Exception("Invalid Hexadecimal Character :" + c.ToString()); 
  
} 
  
}