Codeforces Round #154(Div.2)/253A Boys and Girls(욕심)

2030 단어
A. Boys and Girls
http://codeforces.com/problemset/problem/253/A
time limit per test
1 second
memory limit per test
256 megabytes
input
input.txt
output
output.txt
There are n boys and m girls studying in the class. They should stand in a line so that boys and girls alternated there as much as possible. Let's assume that positions in the line are indexed from left to right by numbers from 1 to n + m. Then the number of integers i(1 ≤ i < n + m) such that positions with indexes i and i + 1 contain children of different genders (position i has a girl and position i + 1has a boy or vice versa) must be as large as possible.
Help the children and tell them how to form the line.
Input
The single line of the input contains two integers n and m (1 ≤ n, m ≤ 100), separated by a space.
Output
Print a line of n + m characters. Print on the i-th position of the line character "B", if the i-th position of your arrangement should have a boy and "G", if it should have a girl.
Of course, the number of characters "B"should equal n and the number of characters "G"should equal m. If there are multiple optimal solutions, print any of them.
Sample test(s)
input
3 3

output
GBGBGB

input
4 2

output
BGBGBB

water.
전체 코드:
/*30ms,100KB*/

#include<cstdio>

int main()
{
	freopen("input.txt", "r", stdin);
	freopen("output.txt", "w", stdout);

	int n, m;
    scanf("%d%d",&n,&m);
	if (n > m)
	{
		int diff = n - m;
		while (m--)
		{
			putchar('B');
			putchar('G');
		}
		while (diff--)
			putchar('B');
	}
	else
	{
		int diff = m - n;
		while (n--)
		{
			putchar('G');
			putchar('B');
		}
		while (diff--)
			putchar('G');
	}
	return 0;
}

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