CodeForces 10D. LCIS 최대 공통 상승 하위 시퀀스 템플릿 문제 + 인쇄 경로

#include <algorithm>
#include <iostream>
#include <cstring>
#include <cstdlib>
#include <cstdio>
#include <queue>
#include <cmath>
#include <stack>
#include <map>
#include <ctime>
#include <iomanip>

#pragma comment(linker, "/STACK:1024000000");
#define EPS (1e-6)
#define LL long long
#define ULL unsigned long long
#define _LL __int64
#define INF 0x3f3f3f3f
#define Mod 1000000007

using namespace std;

int A[510],B[510];

int py[510][510],px[510][510],dp[510][510] = {0};

void Output(int x,int y)
{
    if(x == -1 && y == -1)
        return ;

    Output(px[x][y],py[x][y]);

    if(A[x] == B[y])
        printf("%d ",A[x]);
}

int main()
{
    int n,m,i,j,mlen,x,y;

    scanf("%d",&n);
    for(i = 1;i <= n; ++i)
        scanf("%d",&A[i]);

    scanf("%d",&m);
    for(i = 1;i <= m; ++i)
        scanf("%d",&B[i]);

    int Max = 0,ax,ay;

    for(i = 1;i <= n; ++i)
    {
        mlen = 0,x = -1,y = -1;
        for(j = 1;j <= m; ++j)
        {
            dp[i][j] = dp[i-1][j];
            px[i][j] = i-1,py[i][j] = j;
            if(B[j] < A[i] && dp[i-1][j] > mlen)
                mlen = dp[i-1][j],x = i-1,y = j;

            if(B[j] == A[i])
                dp[i][j] = mlen + 1,px[i][j] = x,py[i][j] = y;
            if(dp[i][j] > Max)
                Max = dp[i][j],ax = i,ay = j;
        }
    }

    if(Max)
        printf("%d
",Max),Output(ax,ay);
    else
        printf("0
");
    return 0;
}