C\#데이터베이스 에 그림 을 저장 하고 그림 을 읽 는 방법

private void button2_Click_1(object sender, System.EventArgs e)
{
string pathName;
if (this.openFileDialog1.ShowDialog()==System.Windows.Forms.DialogResult.OK)
{
pathName = this.openFileDialog1.FileName;
System.Drawing.Image img = System.Drawing.Image.FromFile(pathName);
this.pictureBox1.Image = img;
//          
System.IO.FileStream fs = new System.IO.FileStream(pathName,System.IO.FileMode.Open,System.IO.FileAccess.Read);
byte[] buffByte = new byte[fs.Length];
fs.Read(buffByte,0,(int)fs.Length);
fs.Close();
fs = null;
//  Command  
string comm = @"Insert into table1(img,name) values(@img,@name)";
this.sqlCommand1 = new System.Data.SqlClient.SqlCommand ();
this.sqlCommand1.CommandType = System.Data.CommandType.Text ;
this.sqlCommand1.CommandText = comm;
this.sqlCommand1.Connection = this.sqlConnection1 ;
//  Parameter
this.sqlCommand1.Parameters.Add("@img",System.Data.SqlDbType.Image);
this.sqlCommand1.Parameters[0].Value = https://www.jb51.net/ianakin/archive/2012/02/02/buffByte;
this.sqlCommand1.Parameters.Add("@name",System.Data.SqlDbType.VarChar);
this.sqlCommand1.Parameters[1].Value =https://www.jb51.net/ianakin/archive/2012/02/02/pathName.Substring(pathName.LastIndexOf("\\")+1);
try
{
this.sqlConnection1.Open();
this.sqlCommand1.ExecuteNonQuery();
this.sqlConnection1.Close();
}
catch(System.Exception ee)
{
MessageBox.Show(ee.Message );
}
buffByte = null; 
this.FillListBox();
}

SqlConnection conn=new SqlConnection(@"data source=chenyuming2004VSdotNET;uid=sa;pwd=cym;database=lhf");
conn.Open();
SqlCommand cmd=new SqlCommand("select    from fuser where password='1b'",conn);
SqlDataReader reader=cmd.ExecuteReader();
reader.Read();
MemoryStream buf=new MemoryStream((byte[])reader[0]);
Image image=Image.FromStream(buf,true);
pictureBox1.Image=image;