Leet Code 두 갈래 나무의 앞을 두루 훑어보다
: [1,null,2,3]
1
\
2
/
3
: [1,2,3]
비귀속 (가장 뚜렷한 사고방식):
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public List preorderTraversal(TreeNode root) {
List list = new ArrayList<>();
Stack stack = new Stack<>();
TreeNode cur = root;
if(cur == null) return list;
while(cur != null){
list.add(cur.val);
stack.push(cur);
cur = cur.left;
}
while(!stack.isEmpty()){
cur = stack.pop();
cur = cur.right;
while(cur != null){
list.add(cur.val);
stack.push(cur);
cur = cur.left;
}
}
return list;
}
}
비귀속 (이전 버전의 개선, 코드 간소화):
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public List preorderTraversal(TreeNode root) {
List list = new ArrayList<>();
Stack stack = new Stack<>();
TreeNode cur = root;
while(cur != null || !stack.isEmpty()){
if(cur != null){
stack.push(cur);
list.add(cur.val);
cur=cur.left;
}else{
cur = stack.pop();
cur = cur.right;
}
}
return list;
}
}
귀속:
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public List preorderTraversal(TreeNode root) {
List list = new ArrayList<>();
return test(root,list);
}
List test(TreeNode root, List list){
if(root != null){
list.add(root.val);
test(root.left,list);
test(root.right,list);
}
return list;
}
}