[알고리즘] 프로그래머스 - 키패드 누르기 / 자바

import java.lang.Math;
class Solution {
    String answer = "";
    static int[][] keypad = new int[4][3];
    public String solution(int[] numbers, String hand) {
        int len = numbers.length;
        int num;
        int[] left = new int[2];
        left[0] = 3;
        left[1] = 0;
        
        int[] right = new int[2];
        right[0] = 3;
        right[1] = 2;
        int[] dest = new int[2];
        
        int left_distance = 0;
        int right_distance = 0;
        for(int i = 0 ; i  < len ; i++){
            num = numbers[i];
            if(num ==0 ) num  = 11;
            if(num == 1 || num == 4 || num == 7 ){
                left[0] = num/3;
                left[1] = 0;
                answer+='L';
            }else if(num == 3 || num == 6 || num == 9){
                right[0] = (num/3)-1;
                right[1] = 2;
                answer+='R';
            }else{
                dest[0] = num/3;
                dest[1] = 1;
                left_distance = Math.abs(left[0] - dest[0]) + Math.abs(left[1] - dest[1]);
                right_distance = Math.abs(right[0] - dest[0]) + Math.abs(right[1] - dest[1]);
                if(left_distance > right_distance){
                    right[0] = dest[0];
                    right[1] = dest[1];
                    answer+='R';
                }else if(left_distance == right_distance) {
                    if(hand.equals("left")){
                        left[0] = dest[0];
                        left[1] = dest[1];
                        answer+='L';
                    }else if(hand.equals("right")){
                        right[0] = dest[0];
                        right[1] = dest[1];
                        answer+='R';
                    }
                }else if(left_distance < right_distance){
                    left[0] = dest[0];
                    left[1] = dest[1];
                    answer+='L';
                    }
            }
            
        
        }
        return answer;
    }
    
}

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