527B. Error Correct System【string】

4037 단어 CString
B. Error Correct System
time limit per test
2 seconds
memory limit per test
256 megabytes
input
standard input
output
standard output
Ford Prefect got a job as a web developer for a small company that makes towels. His current work task is to create a search engine for the website of the company. During the development process, he needs to write a subroutine for comparing strings S and T of equal length to be "similar". After a brief search on the Internet, he learned about the Hamming distance between two strings S and T of the same length, which is defined as the number of positions in which S and T have different characters. For example, the Hamming distance between words "permanent"and "pergament"is two, as these words differ in the fourth and sixth letters.
Moreover, as he was searching for information, he also noticed that modern search engines have powerful mechanisms to correct errors in the request to improve the quality of search. Ford doesn't know much about human beings, so he assumed that the most common mistake in a request is swapping two arbitrary letters of the string (not necessarily adjacent). Now he wants to write a function that determines which two letters should be swapped in string S, so that the Hamming distance between a new string S and string T would be as small as possible, or otherwise, determine that such a replacement cannot reduce the distance between the strings.
Help him do this!
Input
The first line contains integer n (1 ≤ n ≤ 200 000) — the length of strings S and T.
The second line contains string S.
The third line contains string T.
Each of the lines only contains lowercase Latin letters.
Output
In the first line, print number x — the minimum possible Hamming distance between strings S and T if you swap at most one pair of letters in S.
In the second line, either print the indexes i and j (1 ≤ i, j ≤ n, i ≠ j), if reaching the minimum possible distance is possible by swapping letters on positions i and j, or print "-1 -1", if it is not necessary to swap characters.
If there are multiple possible answers, print any of them.
Sample test(s)
Input
9
pergament
permanent

Output
1
4 6

Input
6
wookie
cookie

Output
1
-1 -1

Input
4
petr
egor

Output
2
1 2

Input
6
double
bundle

Output
2
4 1

Note
In the second test it is acceptable to print i = 2, j = 3.
제목: 두 단어, 안에 몇 개의 위치에 대응하는 자모가 다르기 때문에 우리는 두 위치의 자모를 교환하여 단어를 더욱 가깝게 할 수 있다.출력 교환 후 몇 개의 위치가 다르고 출력 교환의 두 위치가 있다.실행 가능한 방안이 없으면 출력-1,-1
분석: 두 개의 문자열을 읽고 그 중 하나를 훑어보고 서로 다른 위치를 찾아 위치를 새 수조 c에 기록하고 뒤에 새로운 다른 알파벳을 만날 때마다 그 수조 c를 훑어보고 그 중의 한 위치를 찾을 수 있는지 없는지를 보면 알파벳을 교환할 수 있다.이렇게 쉬워요.
#include<iostream>
#include<cstdio>
#include<cstring>
#include<ctime>
#include<algorithm>
#include <map>
#include <queue>
#include <set>
using namespace std;

//527B   string
string s1,s2;
int n,k;
char a[200001];
int o,q,flag;
int main()
{
    cin>>n>>s1>>s2;
    int j=0;
    o=-1,q=-1;
    for(int i=0;i<n;i++)
    {
        if(s1[i]!=s2[i])
        {
          a[j]=i;
          j++;
        }
        if(j>0&&flag==0)
        {
            for(k=0;k<j;k++)
            {
                if(s2[a[k]]==s1[i])
                {
                    o=i;
                    q=a[k];
                    flag=1;
                }
            }
        }
    }
    if(flag==1){cout<<j-1<<endl;}
    else {cout<<j<<endl;}
    if(o!=-1&&q!=-1)
        {cout<<o+1<<" "<<q+1;}
    else
        {cout<<o<<" "<<q;}

    return 0;
}

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