100일 간의 코드: 2022년을 위한 완벽한 Python Pro 부트캠프 - 11일차(블랙잭)
블랙잭 - 노 프릴
############### Blackjack Project #####################
#Difficulty Normal 😎: Use all Hints below to complete the project.
#Difficulty Hard 🤔: Use only Hints 1, 2, 3 to complete the project.
#Difficulty Extra Hard 😭: Only use Hints 1 & 2 to complete the project.
#Difficulty Expert 🤯: Only use Hint 1 to complete the project.
############### Our Blackjack House Rules #####################
#The deck is unlimited in size.
#There are no jokers.
#The Jack/Queen/King all count as 10.
#The the Ace can count as 11 or 1.
#Use the following list as the deck of cards:
#cards = [11, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 10]
#The cards in the list have equal probability of being drawn.
#Cards are not removed from the deck as they are drawn.
##################### Hints #####################
#Hint 1: Go to this website and try out the Blackjack game:
https://games.washingtonpost.com/games/blackjack/
#Then try out the completed Blackjack project here:
http://blackjack-final.appbrewery.repl.run
#Hint 2: Read this breakdown of program requirements:
http://listmoz.com/view/6h34DJpvJBFVRlZfJvxF
then try to create your own flowchart for the program.
#Hint 3: Download and read this flow chart I've created:
https://drive.google.com/uc?export=download&id=1rDkiHCrhaf9eX7u7yjM1qwSuyEk-rPnt
#Hint 4: Create a deal_card() function that uses the List below to *return* a random card. 11 is the Ace.
import random
from replit import clear
from art import logo
print(logo)
print("Welcome to the game of Blackjack")
def deal_card():
"""Returns a random card from the deck."""
cards = [11, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 10]
card = random.choice(cards)
return card
#Hint 6: Create a function called calculate_score() that takes a List of cards as input and returns the score. Look up the sum() function to help you do this.
def calculate_score(cards):
"""Take a list of cards and return the score calculated from the cards"""
#Hint 7: Inside calculate_score() check for a blackjack (a hand with only 2 cards: ace + 10) and return 0 instead of the actual score. 0 will represent a blackjack in our game.
if sum(cards) == 21 and len(cards) == 2:
return 0
#Hint 8: Inside calculate_score() check for an 11 (ace). If the score is already over 21, remove the 11 and replace it with a 1. You might need to look up append() and remove().
if 11 in cards and sum(cards) > 21:
cards.remove(11)
cards.append(1)
return sum(cards)
#Hint 13: Create a function called compare() and pass in the user_score and computer_score. If the computer and user both have the same score, then it's a draw. If the computer has a blackjack (0), then the user loses. If the user has a blackjack (0), then the user wins. If the user_score is over 21, then the user loses. If the computer_score is over 21, then the computer loses. If none of the above, then the player with the highest score wins.
def compare(user_score, computer_score):
#Bug fix. If you and the computer are both over, you lose.
if user_score > 21 and computer_score > 21:
return "You went over. You lose 😤"
if user_score == computer_score:
return "Draw 🙃"
elif computer_score == 0:
return "Lose, opponent has Blackjack 😱"
elif user_score == 0:
return "Win with a Blackjack 😎"
elif user_score > 21:
return "You went over. You lose 😭"
elif computer_score > 21:
return "Opponent went over. You win 😁"
elif user_score > computer_score:
return "You win 😃"
else:
return "You lose 😤"
def play_game():
#Hint 5: Deal the user and computer 2 cards each using
deal_card()
user_cards = []
computer_cards = []
is_game_over = False
for _ in range(2):
user_cards.append(deal_card())
computer_cards.append(deal_card())
#Hint 11: The score will need to be rechecked with every new card drawn and the checks in Hint 9 need to be repeated until the game ends.
while not is_game_over:
#Hint 9: Call calculate_score(). If the computer or the user has a blackjack (0) or if the user's score is over 21, then the game ends.
user_score = calculate_score(user_cards)
computer_score = calculate_score(computer_cards)
print(f" Your cards: {user_cards}, current score: {user_score}")
print(f" Computer's first card: {computer_cards[0]}")
if user_score == 0 or computer_score == 0 or user_score > 21:
is_game_over = True
else:
#Hint 10: If the game has not ended, ask the user if they want to draw another card. If yes, then use the deal_card() function to add another card to the user_cards List. If no, then the game has ended.
user_should_deal = input("Type 'y' to get another card, type 'n' to pass: ")
if user_should_deal == "y":
user_cards.append(deal_card())
else:
is_game_over = True
#Hint 12: Once the user is done, it's time to let the computer play. The computer should keep drawing cards as long as it has a score less than 17.
while computer_score != 0 and computer_score < 17:
computer_cards.append(deal_card())
computer_score = calculate_score(computer_cards)
print(f" Your final hand: {user_cards}, final score: {user_score}")
print(f" Computer's final hand: {computer_cards}, final score: {computer_score}")
print(compare(user_score, computer_score))
#Hint 14: Ask the user if they want to restart the game. If they answer yes, clear the console and start a new game of blackjack and show the logo from art.py.
while input(f"Do you want to play a game? Type 'y' or 'n': ") == "y":
clear()
play_game()
Reference
이 문제에 관하여(100일 간의 코드: 2022년을 위한 완벽한 Python Pro 부트캠프 - 11일차(블랙잭)), 우리는 이곳에서 더 많은 자료를 발견하고 링크를 클릭하여 보았다
https://dev.to/mike_kameta_aed62d48c2d0f/100-days-of-code-the-complete-python-pro-bootcamp-for-2022-day-11-4cik
텍스트를 자유롭게 공유하거나 복사할 수 있습니다.하지만 이 문서의 URL은 참조 URL로 남겨 두십시오.
우수한 개발자 콘텐츠 발견에 전념
(Collection and Share based on the CC Protocol.)
############### Blackjack Project #####################
#Difficulty Normal 😎: Use all Hints below to complete the project.
#Difficulty Hard 🤔: Use only Hints 1, 2, 3 to complete the project.
#Difficulty Extra Hard 😭: Only use Hints 1 & 2 to complete the project.
#Difficulty Expert 🤯: Only use Hint 1 to complete the project.
############### Our Blackjack House Rules #####################
#The deck is unlimited in size.
#There are no jokers.
#The Jack/Queen/King all count as 10.
#The the Ace can count as 11 or 1.
#Use the following list as the deck of cards:
#cards = [11, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 10]
#The cards in the list have equal probability of being drawn.
#Cards are not removed from the deck as they are drawn.
##################### Hints #####################
#Hint 1: Go to this website and try out the Blackjack game:
https://games.washingtonpost.com/games/blackjack/
#Then try out the completed Blackjack project here:
http://blackjack-final.appbrewery.repl.run
#Hint 2: Read this breakdown of program requirements:
http://listmoz.com/view/6h34DJpvJBFVRlZfJvxF
then try to create your own flowchart for the program.
#Hint 3: Download and read this flow chart I've created:
https://drive.google.com/uc?export=download&id=1rDkiHCrhaf9eX7u7yjM1qwSuyEk-rPnt
#Hint 4: Create a deal_card() function that uses the List below to *return* a random card. 11 is the Ace.
import random
from replit import clear
from art import logo
print(logo)
print("Welcome to the game of Blackjack")
def deal_card():
"""Returns a random card from the deck."""
cards = [11, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 10]
card = random.choice(cards)
return card
#Hint 6: Create a function called calculate_score() that takes a List of cards as input and returns the score. Look up the sum() function to help you do this.
def calculate_score(cards):
"""Take a list of cards and return the score calculated from the cards"""
#Hint 7: Inside calculate_score() check for a blackjack (a hand with only 2 cards: ace + 10) and return 0 instead of the actual score. 0 will represent a blackjack in our game.
if sum(cards) == 21 and len(cards) == 2:
return 0
#Hint 8: Inside calculate_score() check for an 11 (ace). If the score is already over 21, remove the 11 and replace it with a 1. You might need to look up append() and remove().
if 11 in cards and sum(cards) > 21:
cards.remove(11)
cards.append(1)
return sum(cards)
#Hint 13: Create a function called compare() and pass in the user_score and computer_score. If the computer and user both have the same score, then it's a draw. If the computer has a blackjack (0), then the user loses. If the user has a blackjack (0), then the user wins. If the user_score is over 21, then the user loses. If the computer_score is over 21, then the computer loses. If none of the above, then the player with the highest score wins.
def compare(user_score, computer_score):
#Bug fix. If you and the computer are both over, you lose.
if user_score > 21 and computer_score > 21:
return "You went over. You lose 😤"
if user_score == computer_score:
return "Draw 🙃"
elif computer_score == 0:
return "Lose, opponent has Blackjack 😱"
elif user_score == 0:
return "Win with a Blackjack 😎"
elif user_score > 21:
return "You went over. You lose 😭"
elif computer_score > 21:
return "Opponent went over. You win 😁"
elif user_score > computer_score:
return "You win 😃"
else:
return "You lose 😤"
def play_game():
#Hint 5: Deal the user and computer 2 cards each using
deal_card()
user_cards = []
computer_cards = []
is_game_over = False
for _ in range(2):
user_cards.append(deal_card())
computer_cards.append(deal_card())
#Hint 11: The score will need to be rechecked with every new card drawn and the checks in Hint 9 need to be repeated until the game ends.
while not is_game_over:
#Hint 9: Call calculate_score(). If the computer or the user has a blackjack (0) or if the user's score is over 21, then the game ends.
user_score = calculate_score(user_cards)
computer_score = calculate_score(computer_cards)
print(f" Your cards: {user_cards}, current score: {user_score}")
print(f" Computer's first card: {computer_cards[0]}")
if user_score == 0 or computer_score == 0 or user_score > 21:
is_game_over = True
else:
#Hint 10: If the game has not ended, ask the user if they want to draw another card. If yes, then use the deal_card() function to add another card to the user_cards List. If no, then the game has ended.
user_should_deal = input("Type 'y' to get another card, type 'n' to pass: ")
if user_should_deal == "y":
user_cards.append(deal_card())
else:
is_game_over = True
#Hint 12: Once the user is done, it's time to let the computer play. The computer should keep drawing cards as long as it has a score less than 17.
while computer_score != 0 and computer_score < 17:
computer_cards.append(deal_card())
computer_score = calculate_score(computer_cards)
print(f" Your final hand: {user_cards}, final score: {user_score}")
print(f" Computer's final hand: {computer_cards}, final score: {computer_score}")
print(compare(user_score, computer_score))
#Hint 14: Ask the user if they want to restart the game. If they answer yes, clear the console and start a new game of blackjack and show the logo from art.py.
while input(f"Do you want to play a game? Type 'y' or 'n': ") == "y":
clear()
play_game()
Reference
이 문제에 관하여(100일 간의 코드: 2022년을 위한 완벽한 Python Pro 부트캠프 - 11일차(블랙잭)), 우리는 이곳에서 더 많은 자료를 발견하고 링크를 클릭하여 보았다 https://dev.to/mike_kameta_aed62d48c2d0f/100-days-of-code-the-complete-python-pro-bootcamp-for-2022-day-11-4cik텍스트를 자유롭게 공유하거나 복사할 수 있습니다.하지만 이 문서의 URL은 참조 URL로 남겨 두십시오.
우수한 개발자 콘텐츠 발견에 전념 (Collection and Share based on the CC Protocol.)